Use Elimination to solve a + c = 327 and 4a + 1.50c = 978

a + c = 327 4a + 1.50c = 978 Equation 1 is in the correct format. Equation 2 is in the correct format. 4 * (a+c=327) --> 4a + 4c = 1308 1 * (4a+1.50c=978) --> 4a + 1.5c = 978 4a + 4c = 1308 - (4a + 1.5c = 978)-(4a + 1.5c

Use Elimination to solve a + c = 327 and 4a + 1.50c = 978 MathCelebrity logo Image to Crop
Use the elimination method to solve:

a + c = 327

4a + 1.50c = 978

Check Format

Equation 1 is in the correct format.

Check Format

Equation 2 is in the correct format.

Step 1: Multiply Equation 1 by 4:

4 * (a+c=327) --> 4a + 4c = 1308

Step 2: Multiply Equation 2 by 1:

1 * (4a+1.50c=978) --> 4a + 1.5c = 978

Step 3: Equation 1 - Equation 2:

4a + 4c = 1308 - (4a + 1.5c = 978)
-(4a + 1.5c = 978)

4c - 1.5c = 1308 - 978

Step 4: simplify and solve for c:

2.5c = 330

c  =  330
  2.5

c = 132

Step 5: Rearrange Equation 1 to solve for a:

1a = 327 - 1c

Divide each side by 1

a  =  327 - 1c
  1

Step 6: Plug c = 132 into equation 1:
a  =  327 - 1(132)
  1

a  =  327 - 132
  1

a  =  195
  1

a = 195


What is the Answer?

How does the Simultaneous Equations Calculator work?

Free Simultaneous Equations Calculator - Solves a system of simultaneous equations with 2 unknowns using the following 3 methods:
1) Substitution Method (Direct Substitution)
2) Elimination Method
3) Cramers Method or Cramers Rule Pick any 3 of the methods to solve the systems of equations 2 equations 2 unknowns
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What 7 concepts are covered in the Simultaneous Equations Calculator?

cramers rulean explicit formula for the solution of a system of linear equations with as many equations as unknownseliminateto remove, to get rid of or put an end toequationa statement declaring two mathematical expressions are equalsimultaneous equations two or more algebraic equations that share variablessubstituteto put in the place of another. To replace one value with anotherunknowna number or value we do not knowvariableAlphabetic character representing a number

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